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A 5 amp fuse wire can withstand a maximum power of 1 W in circuit. The resistance of the fuse wire is
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Verified Answer
The correct answer is:
$0.04 \Omega$
Power $P=i^2 R$
$\Rightarrow \quad R=\frac{P}{i^2}$
given, $P=1 \mathrm{~W}$, and $i=5 \mathrm{~A}$
$\therefore \quad R=\frac{1}{(5)^2}=0.04 \Omega$
$\Rightarrow \quad R=\frac{P}{i^2}$
given, $P=1 \mathrm{~W}$, and $i=5 \mathrm{~A}$
$\therefore \quad R=\frac{1}{(5)^2}=0.04 \Omega$
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