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Question: Answered & Verified by Expert
A 5 watt source emits monochromatic light of wavelength 5000Å. When placed 0.5 m away, it liberates photoclectrons from a photosensitive metallic surface. When the source is moved to a distance of 1.0 m, the number of photoelectrons liberated will be reduced by a factor of :
PhysicsDual Nature of MatterNEETNEET 2007
Options:
  • A 8
  • B 16
  • C 2
  • D 4
Solution:
2044 Upvotes Verified Answer
The correct answer is: 4
Intensity is given by
I=p4πd2
where p= power of source
d= distance
We know (assume) that light to spread out uniformly is all direction i.e. spherical source.
I1d2 or I1I2=d22d12or I1I2=(10.5)2I1I2=4or I2=I14

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