A 70 kg man standing on ice throws a 3 kg body horizontally at 8 m s - 1 . The friction coefficient between the ice and his feet is 0 . 02 . The distance, through which the man slip is

Question

A 70 kg man standing on ice throws a 3 kg body horizontally at 8 m s - 1 . The friction coefficient between the ice and his feet is 0 . 02 . The distance, through which the man slip is, 0 . 3 m, 2 m, 1 m, ∞

MARKS App · Accepted Answer

At the time of throwing body, velocity gained by man is v 0 = 3 × 8 70 = 24 70 m/s ∴ Stopping distance s = v 0 2 2 μ g Or s = 2 4 × 24 70 × 70 × 2 × 0.02 × 10 = 576 49 × 40 = 144 490 = 0.3 m

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