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$A B$ is an ionic solid. The ionic radii of $A^{+}$and $B^{-}$ are respectively $r_c$ and $r_a$. Lattice energy of $A B$ is proportional to :
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The correct answer is:
$\frac{1}{\left(r_c+r_a\right)}$
The lattice becomes stronger (i.e., the lattice energy $U$ becomes more negative), as $r$ the inter ionic distance decreases. $U$ is proportional to $\frac{1}{r}$ or $U \propto \frac{1}{\left(r_c+r_a\right)}$
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