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A balloon contains $500 \mathrm{~m}^3$ of helium at $27^{\circ} \mathrm{C}$ and 1 atmosphere pressure. The volume of the helium at $-3^{\circ} \mathrm{C}$ temperature and 0.5 atmosphere pressure will be
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$900 \mathrm{~m}^3$
Using gas equation law
$\begin{aligned} \frac{p_1 V_1}{T_1} & =\frac{p_2 V_2}{T_2} \\ \text { or } \frac{1 \times 500}{300} & =\frac{0.5 \times V_2}{270} \\ V_2 & =900 \mathrm{~m}^3\end{aligned}$
$\begin{aligned} \frac{p_1 V_1}{T_1} & =\frac{p_2 V_2}{T_2} \\ \text { or } \frac{1 \times 500}{300} & =\frac{0.5 \times V_2}{270} \\ V_2 & =900 \mathrm{~m}^3\end{aligned}$
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