A block moves down a smooth inclined plane of inclination θ . Its velocity on reaching the bottom is v . If it slides down a rough inclined plane of same inclination, its velocity on reaching the bottom is v / n , where n is a number greater than 1. The coefficient of friction is given by

Question

A block moves down a smooth inclined plane of inclination θ . Its velocity on reaching the bottom is v . If it slides down a rough inclined plane of same inclination, its velocity on reaching the bottom is v / n , where n is a number greater than 1. The coefficient of friction is given by, μ = tan ⁡ θ 1 - 1 n 2, μ = cot ⁡ θ 1 - 1 n 2, μ = tan θ 1 - 1 n 2 1/2, μ = cot θ 1 - 1 n 2 1/2

MARKS App · Accepted Answer

For smooth, v 2 = 2 g s i n θ s . . . ( 1 ) For rough, v n 2 = 2 g s i n θ - μ c o s θ S . . . ( 2 ) on solving, μ = 1 - 1 n 2 t a n θ

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