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A block of mass $M$ is held against a rough vertical wall by pressing it with a finger. If the coefficient of friction between the block and the wall is $\mu$ and the acceleration due to gravity is $g$, calculate the minimum force required to be applied by the finger to hold the block against the wall.
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Verified Answer
As given that, mass of the block $=M$
Coefficient of friction between the block and the wall $=\mu$.
Let $F$ force be applied by finger on the block to hold the block against the wall. The nomral reaction of mass be $N$ and force of friction acting upward be $f$. In equilibrium, vertical and horizontal forces should be balanced separately.
$$
f=M g
$$
(Given), $F=N$
As we know that, Force of friction $(f)=\mu N$
$$
=\mu F_{\ldots} \text { (iii) } \quad(\because F=N)
$$

From eqs. (i) and (iii), we have,
$$
\mu F=M g
$$
or $F=\frac{M g}{\mu}$
It is the minimum force to hold the block against the wall at rest.
Coefficient of friction between the block and the wall $=\mu$.
Let $F$ force be applied by finger on the block to hold the block against the wall. The nomral reaction of mass be $N$ and force of friction acting upward be $f$. In equilibrium, vertical and horizontal forces should be balanced separately.
$$
f=M g
$$
(Given), $F=N$
As we know that, Force of friction $(f)=\mu N$
$$
=\mu F_{\ldots} \text { (iii) } \quad(\because F=N)
$$

From eqs. (i) and (iii), we have,
$$
\mu F=M g
$$
or $F=\frac{M g}{\mu}$
It is the minimum force to hold the block against the wall at rest.
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