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A block of mass $\mathrm{m}$ is sliding down an inclined plane with constant speed. At a certain instant $\mathrm{t}_{0}$, its height above the ground is $\mathrm{h}$. The coefficient of kinetic friction between the block and the plane is $\mu$. If the block reaches the ground at a later instant $\mathrm{t}_{\mathrm{g}}$, then the energy dissipated by friction in the time interval $\left(\mathrm{t}_{\mathrm{g}}-\mathrm{t}_{0}\right)$ is-
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$\mathrm{mgh}$ )
$\begin{array}{l}
\mathrm{W}_{\mathrm{f}}+\mathrm{W}_{\mathrm{mg}}=\Delta \mathrm{K} . \mathrm{E} .,(\Delta \mathrm{K} . \mathrm{E} \cdot=0) \\
\mathrm{W}_{\mathrm{f}}=-\mathrm{W}_{\mathrm{mg}} \\
\mathrm{W}_{\mathrm{f}}=-\mathrm{mgh} \\
\therefore \text { Energy dissipated }=\mathrm{mgh}
\end{array}$
\mathrm{W}_{\mathrm{f}}+\mathrm{W}_{\mathrm{mg}}=\Delta \mathrm{K} . \mathrm{E} .,(\Delta \mathrm{K} . \mathrm{E} \cdot=0) \\
\mathrm{W}_{\mathrm{f}}=-\mathrm{W}_{\mathrm{mg}} \\
\mathrm{W}_{\mathrm{f}}=-\mathrm{mgh} \\
\therefore \text { Energy dissipated }=\mathrm{mgh}
\end{array}$
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