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A body $A$ of mass $M$ while falling vertically downwards under gravity breaks into two parts; a body B of mass $1 / 3 \mathrm{M}$ and a body $\mathrm{C}$ of mass $2 / 3 \mathrm{M}$. The centre of mass of bodies $\mathrm{B}$ and $\mathrm{C}$ taken together shifts compared to that of body $\mathrm{A}$ towards
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The correct answer is:
does not shift
does not shift
No horizontal external force is acting
$$
\begin{aligned}
& \therefore \mathrm{a}_{\mathrm{cm}}=0 \\
& \text { since } \mathrm{v}_{\mathrm{cm}}=0 \\
& \therefore \Delta \mathrm{x}_{\mathrm{cm}}=0
\end{aligned}
$$
$$
\begin{aligned}
& \therefore \mathrm{a}_{\mathrm{cm}}=0 \\
& \text { since } \mathrm{v}_{\mathrm{cm}}=0 \\
& \therefore \Delta \mathrm{x}_{\mathrm{cm}}=0
\end{aligned}
$$
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