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A body centred cubic lattice is made up of two different types of atoms X and Y. Atom X occupies the body centre and atoms $\mathrm{Y}$ occupy the corner positions. One of the corners is left unoccupied per unit cell. The empirical formula of it is
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The correct answer is:
$\mathrm{X}_8 \mathrm{Y}_7$
No. of X atoms per unit cell $=1 \times 8=8$
No. of $Y$ atoms per unit cell $=\left[\left(8 \times \frac{1}{8}\right) \times 8\right]-1=7$
$\Rightarrow$ Empirical formula $=\mathrm{X}_8 \mathrm{Y}_7$
No. of $Y$ atoms per unit cell $=\left[\left(8 \times \frac{1}{8}\right) \times 8\right]-1=7$
$\Rightarrow$ Empirical formula $=\mathrm{X}_8 \mathrm{Y}_7$
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