Search any question & find its solution
Question:
Answered & Verified by Expert
A body is thrown with a velocity of $9.8 \mathrm{~m} / \mathrm{s}$ making an angle of $30^{\circ}$ with the horizontal. It will hit the ground after a time
Options:
Solution:
1759 Upvotes
Verified Answer
The correct answer is:
1 s
$\begin{aligned} & \text { The time of flight }=\frac{2 u \sin \theta}{g} \\ & =\frac{2 \times 9.8 \times \sin 30^{\circ}}{9.8}=1 \mathrm{~s}\end{aligned}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.