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A Body moves $6 m$ north. $8 m$ east and $10 m$ vertically upwards, what is its resultant displacement from initial position
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$10 \sqrt{2} m$
$\begin{gathered}\bar{r}=x \hat{i}+y \hat{j}+z \hat{k} \quad \therefore r=\sqrt{x^2+y^2+z^2} \\ l=\sqrt{6^2+8^2+10^2}=10 \sqrt{2} \mathrm{~m}\end{gathered}$
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