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Question: Answered & Verified by Expert
A body of mass 1 kg is connected to a string and is undergoing a complete vertical circular motion of radius 1 m. If it is barely able to complete the vertical circle, then the difference in its kinetic energy at the top and bottom of the circle is (Take g=10 ms-2)
PhysicsLaws of MotionNEET
Options:
  • A 10 J
  • B 20 J
  • C 30 J
  • D 50 J
Solution:
1203 Upvotes Verified Answer
The correct answer is: 20 J
Difference in KE= 1 2 m[ ( 5gr ) 2 ( gr ) 2 ]

=2mgr =20 J

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