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Question: Answered & Verified by Expert
A body of mass 10 kg is moving on a horizontal surface by applying a force of 10 N in the forward direction. The body moves with a constant velocity of 0.2 m s-1. Work done by the force of friction in the first 10 seconds is
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Options:
  • A -20 J
  • B 10 J
  • C 20 J
  • D -5 J
Solution:
1490 Upvotes Verified Answer
The correct answer is: -20 J
Since, body moves with constant velocity. So, net force on the body is zero.



Here,   N = mg

              F = f

∴        W=f·s= fs cos 180°

                   = –fs= –10 × 2 = –20 J

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