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A body of mass $10 \mathrm{mg}$ is moving with a velocity of $100 \mathrm{~ms}^{-1}$. The wavelength of de-Broglie wave associated with it would be ( $h=6.63 \times 10^{-34} \mathrm{Js}$ )
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The correct answer is:
$6.63 \times 10^{-31} \mathrm{~m}$
$m=10 \mathrm{mg}=10 \times 10^{-6} \mathrm{~kg}$
$$
\begin{aligned}
v &=100 \mathrm{~ms}^{-1} \\
\lambda &=\frac{h}{m v}=\frac{6.63 \times 10^{-34}}{10 \times 10^{-6} \times 100} \\
&=6.63 \times 10^{-31} \mathrm{~m}
\end{aligned}
$$
$$
\begin{aligned}
v &=100 \mathrm{~ms}^{-1} \\
\lambda &=\frac{h}{m v}=\frac{6.63 \times 10^{-34}}{10 \times 10^{-6} \times 100} \\
&=6.63 \times 10^{-31} \mathrm{~m}
\end{aligned}
$$
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