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Question: Answered & Verified by Expert

A body of mass 2 kg moves under a force of 2i^+3j^+5k^N It starts from rest and was at the origin initially. After 4 s, its new coordinates are 8,b,20. The value of b is ______.

(Round off to the Nearest Integer)

PhysicsMotion In One DimensionJEE MainJEE Main 2021 (16 Mar Shift 2)
Solution:
2050 Upvotes Verified Answer
The correct answer is: 12

a=Fm=2i^+3j^+5k^2

=i^+1.5j^+2.5k^

τ=ut+12at2

=0+12i^+1.5j^+2.5k^16

=8i^+12j^+20k^

b=12

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