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A bucket full of water tied with the help of a $2 \mathrm{~m}$ long string performs a vertical circular motion. The minimum angular velocity of the bucket at the uppermost point so that water will not fall will be:
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The correct answer is:
$\sqrt{5} \mathrm{rad} / \mathrm{s}$
as water should not fall
$w w^2 r=m g$
$\omega=\sqrt{\frac{8}{\gamma}}=\sqrt{\frac{10}{2}}=\sqrt{5}$
$w w^2 r=m g$
$\omega=\sqrt{\frac{8}{\gamma}}=\sqrt{\frac{10}{2}}=\sqrt{5}$
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