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Question: Answered & Verified by Expert
A buffer solution is prepared by mixing $10 \mathrm{~mL}$ of $1.0 \mathrm{M}$ acetic acid and $20 \mathrm{~mL}$ of $0.5 \mathrm{M}$ sodium acetate and then diluted to $100 \mathrm{~mL}$ with distilled water, The $\mathrm{pH}$ of the buffer solution is ( $\mathrm{p} K_a$ of acetic acid is 4.76 )
ChemistryIonic EquilibriumAP EAMCETAP EAMCET 2019 (20 Apr Shift 2)
Options:
  • A 4.84
  • B 5.21
  • C 4.34
  • D 4.76
Solution:
2780 Upvotes Verified Answer
The correct answer is: 4.76
Milliequivalents of acetic acid $=10 \mathrm{~mL} \times 1.0 \mathrm{M}$

Milliequivalents of sodium acetate $=2.0 \mathrm{~mL} \times 0.5 \mathrm{M}$ From Henderson equation,
$$
\mathrm{pH}=\mathrm{p} K_a+\log \left[\frac{\text { salt }}{\text { acid }}\right]
$$

Here, $\quad \mathrm{p} K_a=4.76$
[For acetic acid]
$$
\begin{aligned}
\because \quad \mathrm{pH} & =4.76+\log \left(\frac{0.5 \times 20}{10 \times 1.0}\right) \\
\mathrm{pH} & =4.76
\end{aligned}
$$

Hence, option (d) is correct.

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