A bus starts from rest and moves with constant acceleration $ 8 \mathrm{~m} \mathrm{~s}^{-2} $. At the same time, a car travelling with constant velocity $ 16 \mathrm{~m} \mathrm{~s}^{-1} $ overtakes and passes the bus. At what distance, bus overtakes the car?

Question

A bus starts from rest and moves with constant acceleration $ 8 \mathrm{~m} \mathrm{~s}^{-2} $. At the same time, a car travelling with constant velocity $ 16 \mathrm{~m} \mathrm{~s}^{-1} $ overtakes and passes the bus. At what distance, bus overtakes the car?, $ 24 \mathrm{~m} $, $ 32 \mathrm{~m} $, $ 60 \mathrm{~m} $, $ 64 \mathrm{~m} $

MARKS App · Accepted Answer

Let the bus overtakes the car after time t and at distance d . Bus, S = u t + 1 2 a t 2 d = 1 2 × 8 × t 2 … i Car: S = v t d = 16 t … ii by i and ii t = sec , d = 64 m .

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