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A car starts from rest and accelerates uniformly to a speed of $180 \mathrm{kmh}^{-1}$ in $10 \mathrm{~s}$. The distance covered by the car in this time interval is
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The correct answer is:
250 m
Speed of car, $v=180 \mathrm{kmh}^{-1}=50 \mathrm{~ms}^{-1}$ and time, $t=10 \mathrm{~s}$
$\therefore$ Acceleration of the car,
$a=\frac{v-u}{t}=\frac{50-0}{10}=5 \mathrm{~ms}^{-2}$
Thus, the distance covered by the car,
$s=\frac{1}{2} a t^2=\frac{1}{2} \times 5 \times(10)^2=250 \mathrm{~m}$
$\therefore$ Acceleration of the car,
$a=\frac{v-u}{t}=\frac{50-0}{10}=5 \mathrm{~ms}^{-2}$
Thus, the distance covered by the car,
$s=\frac{1}{2} a t^2=\frac{1}{2} \times 5 \times(10)^2=250 \mathrm{~m}$
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