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A certain metal sulphide, $M S_2$, is used extensively as a high temperature lubricant. If $\mathrm{MS}_2$ is $40.06 \%$ by mass sulphur, metal $M$ has atomic mass.
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The correct answer is:
$96 \mathrm{u}$
$96 \mathrm{u}$
$M S_2=M+32 \times 2=M+64$
$\%$ of sulphur $=\left(\frac{64}{M+64}\right) \times 100=40.06$
$M+64=\frac{6400}{40.06}$
$M+64=160$
$M=160-64=96$ u
$\%$ of sulphur $=\left(\frac{64}{M+64}\right) \times 100=40.06$
$M+64=\frac{6400}{40.06}$
$M+64=160$
$M=160-64=96$ u
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