A charge of magnitude 1.6 × 10 - 19 C is moving in a circle of radius 5 cm in a uniform magnetic field 0.5 T . After applying E = 0.15 V m - 1 charge starts moving in a straight line mass of charge will be

Question

A charge of magnitude 1.6 × 10 - 19 C is moving in a circle of radius 5 cm in a uniform magnetic field 0.5 T . After applying E = 0.15 V m - 1 charge starts moving in a straight line mass of charge will be, 2 3 × 10 - 20 kg, 4 3 × 10 - 20 kg, 6 3 × 10 - 20 kg, 1 3 × 10 - 20 kg

MARKS App · Accepted Answer

For a particle to move in a circle under magnetic field q V B = m v 2 R ...(i) For a particle to move in a straight line In both magnetic field and electric field q V B = 2 E ⇒ V = E B ...(ii) From (i) to (ii) q B = m v R = m . E B R ⇒ m = q E 2 R E = 1.6 × 10 - 13 × 0.5 2 × 10 - 2 0.15 kg = 4 3 × 10 − 20 kg

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