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A charge of magnitude ' $2 \mathrm{e}$ ' and mass ' $4 \mathrm{~m}$ ' is moving in an electric Field E. The acceleration imparted to the above charge is
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Verified Answer
The correct answer is:
$\frac{E e}{2 m}$
Force, $\mathrm{F}=$ charge $\times$ Electric field $=2 \mathrm{eE}$
$$
\text { Acceleration }=\frac{\text { Force }}{\text { Mass }}=\frac{2 \mathrm{eE}}{4 \mathrm{~m}}=\frac{\mathrm{eE}}{2 \mathrm{~m}}
$$
$$
\text { Acceleration }=\frac{\text { Force }}{\text { Mass }}=\frac{2 \mathrm{eE}}{4 \mathrm{~m}}=\frac{\mathrm{eE}}{2 \mathrm{~m}}
$$
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