Search any question & find its solution
Question:
Answered & Verified by Expert
A charge $Q \mu C$ is placed at the centre of a cube. The flux coming out from any one of its faces will be (in SI unit)
Options:
Solution:
2966 Upvotes
Verified Answer
The correct answer is:
$\frac{Q}{6 \varepsilon_0} \times 10^{-6}$
According to Gauss law, total electric flux through a closed surface is
$\phi_{\text {net }}=\frac{q}{\varepsilon_0}$
$\therefore$ Total electric flux through the cube is
$\phi_T=\frac{Q \times 10^{-6}}{\varepsilon_0}$
Since charge is placed at the centre of the cube, therefore flux through each face is same.
Hence, $\phi=\frac{1}{6} \phi_T=\frac{1}{6} \times \frac{Q \times 10^{-6}}{\varepsilon_0}$
$\phi_{\text {net }}=\frac{q}{\varepsilon_0}$
$\therefore$ Total electric flux through the cube is
$\phi_T=\frac{Q \times 10^{-6}}{\varepsilon_0}$
Since charge is placed at the centre of the cube, therefore flux through each face is same.
Hence, $\phi=\frac{1}{6} \phi_T=\frac{1}{6} \times \frac{Q \times 10^{-6}}{\varepsilon_0}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.