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A charged particle is moving in an electric field of $3 \times 10^{-10} \mathrm{Vm}^{-1}$ with mobility $2.5 \times 10^6 \mathrm{~m}^2 / \mathrm{V}$-s, its drift velocity is
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Verified Answer
The correct answer is:
$7.5 \times 10^{-4} \mathrm{~m} / \mathrm{s}$
Given, electric field, $E=3 \times 10^{-10} \mathrm{Vm}^{-1}$
Mobility, $\mu=25 \times 10^6 \mathrm{~m}^2 / \mathrm{V}-\mathrm{s}$
If drift velocity is $v_d$, then we know that
$$
\begin{aligned}
\mu & =\frac{v_d}{E} \Rightarrow v_d=\mu E \\
& =25 \times 10^6 \times 3 \times 10^{-10}=7.5 \times 10^{-4} \mathrm{~m} / \mathrm{s}
\end{aligned}
$$
Mobility, $\mu=25 \times 10^6 \mathrm{~m}^2 / \mathrm{V}-\mathrm{s}$
If drift velocity is $v_d$, then we know that
$$
\begin{aligned}
\mu & =\frac{v_d}{E} \Rightarrow v_d=\mu E \\
& =25 \times 10^6 \times 3 \times 10^{-10}=7.5 \times 10^{-4} \mathrm{~m} / \mathrm{s}
\end{aligned}
$$
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