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A closed loop PQRS carrying a current is placed in a uniform magnetic field. If the magnetic forces on segments $P S, S R$ and $R Q$ are $F_1, F_2$ and $F_3$ respectively and are in the plane of the paper and along the directions shown, the directions shown, the force on the segment $Q P$ is
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Verified Answer
The correct answer is:
$\sqrt{\left(F_3-F_1\right)^2+F_2^2}$
\(\begin{aligned}
& F_4 \sin \theta=F_2 \\
& F_4 \cos \theta=\left(F_3-F_1\right) \\
\therefore \quad & F_4=\sqrt{\left(F_3-F_1\right)^2+F_2^2}
\end{aligned}\)
For a closed loop there is no translation.
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