Search any question & find its solution
Question:
Answered & Verified by Expert
A coil of 40 henry inductance is connected in series with a resistance of $8 \mathrm{ohm}$ and the combination is joined to the terminals of a 2 volt battery. The time constant of the circuit is
Options:
Solution:
1534 Upvotes
Verified Answer
The correct answer is:
5 seconds
Time constant is $\mathrm{L} / \mathrm{R}$
Given, $L=40 \mathrm{H} \& \mathrm{R}=8 \Omega$
$\therefore \tau=40 / 8=5 \mathrm{sec} .$
Given, $L=40 \mathrm{H} \& \mathrm{R}=8 \Omega$
$\therefore \tau=40 / 8=5 \mathrm{sec} .$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.