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A common emitter amplifier has a voltage gain of 50, an input impedance of $100 \Omega$ and an output impedence of 200 $\Omega$. the power gain of the amplifier is:
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The correct answer is:
1250
$\begin{aligned}
\text { Voltage gain } & =(\beta)\left(\frac{\mathrm{R}_0}{\mathrm{R}_i}\right)=50 \\
\Rightarrow \quad \beta & =\frac{50 \times 100}{200}=25 \\
\text { Power gain } & =(125)^2 \times \frac{200}{100} \\
& =(125)^2 \times \frac{200}{100} \\
& =625 \times \frac{200}{100} \\
& =1250
\end{aligned}$
\text { Voltage gain } & =(\beta)\left(\frac{\mathrm{R}_0}{\mathrm{R}_i}\right)=50 \\
\Rightarrow \quad \beta & =\frac{50 \times 100}{200}=25 \\
\text { Power gain } & =(125)^2 \times \frac{200}{100} \\
& =(125)^2 \times \frac{200}{100} \\
& =625 \times \frac{200}{100} \\
& =1250
\end{aligned}$
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