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A compound $\mathrm{M}_{\mathrm{p}} \mathrm{X}_{\mathrm{q}}$ has cubic close packing (ccp) arrangement of $X$. Its unit cell structure is shown below. The empirical formula of the compound is
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The correct answer is:
$\mathrm{MX}_{2}$
No. of M atoms $=\frac{1}{4} \times 4+1=1+1=2$
No. of $X$ atoms $=\frac{1}{2} \times 6+\frac{1}{8} \times 8=3+1=4$
So, formula $=\mathrm{M}_{2} \mathrm{X}_{4}=\mathrm{MX}_{2}$
No. of $X$ atoms $=\frac{1}{2} \times 6+\frac{1}{8} \times 8=3+1=4$
So, formula $=\mathrm{M}_{2} \mathrm{X}_{4}=\mathrm{MX}_{2}$
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