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A conducting square loop of side $\mathrm{L}$ and resistance $\mathrm{R}$ moves in its plane with a uniform velocity v perpendicular to one of its side. A magnetic induction $\mathrm{B}$ constant in time and space, pointing perpendicular and into the plane of the loop exists everywhere.
The current induced in the loop is
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The current induced in the loop is
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The correct answer is:
zero
Since the magnetic field is uniform the flux $f$ through the square loop at any time $t$ is constant, because
$\begin{array}{l}
\mathrm{f}=\mathrm{B} \times \mathrm{A}=\mathrm{B} \times \mathrm{L}^{2}=\text { constant } \\
\therefore \varepsilon=-\frac{\mathrm{d} \phi}{\mathrm{dt}}=\text { zero }
\end{array}$
$\begin{array}{l}
\mathrm{f}=\mathrm{B} \times \mathrm{A}=\mathrm{B} \times \mathrm{L}^{2}=\text { constant } \\
\therefore \varepsilon=-\frac{\mathrm{d} \phi}{\mathrm{dt}}=\text { zero }
\end{array}$
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