A converging lens forms a real image $I$ of an object on its principal axis. A rectangular slab of refractive index $\mu$ and thickness $x$ is introduced between $I$ and the lens, $I$ will move

Question

A converging lens forms a real image $I$ of an object on its principal axis. A rectangular slab of refractive index $\mu$ and thickness $x$ is introduced between $I$ and the lens, $I$ will move, towards the lens $(\mu-1) x$, towards the lens by $\left(1-\frac{1}{\mu}\right) x$, away from the lens by $(\mu-1) x$, away from the lens by $\left(1-\frac{1}{\mu}\right) x$.

MARKS App · Accepted Answer

Due to insertion of slab, the optical path increases by x / μ , where x is thickness of slab. Therefore the converging point will shift away by [ x − μ x ​ ] = x ( 1 − μ 1 ​ ) .

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