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A cricket fielder can throw the cricket ball with a speed vo. If he throws the ball while running with speed u at an angle θ to the horizontal, what will be time of flight?
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The correct answer is:
$\frac{2{{v}_{o}}sin\theta }{g}$
Correct Option is : (B)
$\frac{2{{v}_{o}}sin\theta }{g}$
$\frac{2{{v}_{o}}sin\theta }{g}$
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