Search any question & find its solution
Question:
Answered & Verified by Expert
A current of $0.1 \mathrm{~A}$ circulates around a coil of 100 turns and having a radius equal to $5 \mathrm{~cm}$. The magnetic field set up at the celutre of the coil is
$\left(\mu_0=4 \pi \times 10^{-7}\right.$ weber $/$ ampere - metre $)$
Options:
$\left(\mu_0=4 \pi \times 10^{-7}\right.$ weber $/$ ampere - metre $)$
Solution:
2075 Upvotes
Verified Answer
The correct answer is:
$4 \pi \times 10^{-5}$ tesla
$B=\frac{\mu_0 N i}{2 r}=\frac{4 \pi \times 10^{-7} \times 100 \times 0.1}{2 \times 5 \times 10^{-2}}=4 \pi \times 10^{-5} \text { Tes/a }$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.