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Question: Answered & Verified by Expert
A current of $0.1 \mathrm{~A}$ circulates around a coil of 100 turns and having a radius equal to $5 \mathrm{~cm}$. The magnetic field set up at the celutre of the coil is
$\left(\mu_0=4 \pi \times 10^{-7}\right.$ weber $/$ ampere - metre $)$
PhysicsMagnetic Effects of CurrentJEE Main
Options:
  • A $4 \pi \times 10^{-5}$ tesla
  • B $8 \pi \times 10^{-5}$ tesla
  • C $4 \times 10^{-5}$ tesla
  • D $2 \times 10^{-5}$ tesla
Solution:
2075 Upvotes Verified Answer
The correct answer is: $4 \pi \times 10^{-5}$ tesla
$B=\frac{\mu_0 N i}{2 r}=\frac{4 \pi \times 10^{-7} \times 100 \times 0.1}{2 \times 5 \times 10^{-2}}=4 \pi \times 10^{-5} \text { Tes/a }$

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