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A current of 2A is increasing at a rate of 4 A/s through a coil of inductance 2 H. The energy stored in the inductor per unit time in given instant is
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Verified Answer
The correct answer is:
16 J/s
Potential difference across coil is
or V = (2) (4) = 8V
Now energy stored per unit time
= power = Vi
= (8) (2) = 16 J/s
or V = (2) (4) = 8V
Now energy stored per unit time
= power = Vi
= (8) (2) = 16 J/s
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