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A cylindrical magnetic rod has length $5 \mathrm{~cm}$ and diameter $1 \mathrm{~cm}$. It has uniform magnetization $5 \cdot 3 \times 10^{3} \frac{\mathrm{A}}{\mathrm{m}^{3}}$. Its net magnetic dipole moment is nearly $\left(\pi=\frac{22}{7}\right)$
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The correct answer is:
$2 \times 10^{-2} \frac{\mathrm{J}}{\mathrm{T}}$
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