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A cylindrical tube of uniform cross-sectional area $A$ is fitted with two air tight frictionless pistons. The pistons are connected to each other by a metallic wire. Initially, the pressure of the gas is $p_0$ and temperature is $T_0$, atmospheric pressure is also $p_0$. Now, the temperature of the gas is increased to $2 T_0$, the tension of wire will be
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$p_0 A$
Volume of the gas is constant i.e. $V$ = constant
$\therefore p \propto T$ i.e. pressure will be doubled if temperature is doubled.
Let $F$ be the tension in the wire. Then, equilibrium of any one pipes gives.
$F=\left(p-p_0\right) A=\left(2 p_0-p_0\right) A=p_0 A$
$\therefore p \propto T$ i.e. pressure will be doubled if temperature is doubled.
Let $F$ be the tension in the wire. Then, equilibrium of any one pipes gives.
$F=\left(p-p_0\right) A=\left(2 p_0-p_0\right) A=p_0 A$
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