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A deuteron of kinetic energy $50 \mathrm{keV}$ is describing a circular orbit of radius 0.5 metre in a plane perpendicular to the magnetic field $\mathrm{B}$. The kinetic energy of the proton that describes a circular orbit of radius 0.5 metre in the same plane with the same $\mathrm{B}$ is
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$100 \mathrm{keV}$
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