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Question: Answered & Verified by Expert
A deuteron of kinetic energy $50 \mathrm{keV}$ is describing a circular orbit of radius 0.5 metre in a plane perpendicular to the magnetic field $\mathrm{B}$. The kinetic energy of the proton that describes a circular orbit of radius 0.5 metre in the same plane with the same $\mathrm{B}$ is
PhysicsMagnetic Effects of CurrentBITSATBITSAT 2016
Options:
  • A $25 \mathrm{keV}$
  • B $50 \mathrm{keV}$
  • C $200 \mathrm{keV}$
  • D $100 \mathrm{keV}$
Solution:
1085 Upvotes Verified Answer
The correct answer is: $100 \mathrm{keV}$
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