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A die is thrown. Let $A$ be the event that the number obtained is greater than 3 . Let $B$ be the event that the number obtained is less than 5 . Then $P(A \cup B)$ is
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The correct answer is:
1
1
$$
A=\{4,5,6\}, B=\{1,2,3,4\} \text {. }
$$
Obviously $P(A \cup B)=1$.
A=\{4,5,6\}, B=\{1,2,3,4\} \text {. }
$$
Obviously $P(A \cup B)=1$.
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