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Question: Answered & Verified by Expert
A disc is performing pure rolling on a smooth stationary surface with constant angular velocity as shown in the figure. At any instant, for the lowermost point of the disc.

PhysicsRotational MotionNEET
Options:
  • A Velocity is v, acceleration is zero
  • B Velocity is zero, acceleration is zero
  • C Velocty is v, acceleration is v2R
  • D Velocity is zero, acceleration is nonzero
Solution:
1521 Upvotes Verified Answer
The correct answer is: Velocity is zero, acceleration is nonzero
From figure



Vnetfor lowest point=v-Rω=v-v=0

and Acceleration=v2R+ O=v2R

(Since linear speed is constant)

Hence (D)

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