A disc of mass m and radius R , is placed on a smooth fixed surface. Point A is the geometrical centre of the disc while point B is the centre of mass of the disc. The moment of inertia of the disc about an axis through its centre of mass and perpendicular to the plane of the figure is I . A constant force F is applied to the top of the disc. The acceleration of the centre A of the disc at the instant B is below A (on the same vertical line) will be :

Question

A disc of mass m and radius R , is placed on a smooth fixed surface. Point A is the geometrical centre of the disc while point B is the centre of mass of the disc. The moment of inertia of the disc about an axis through its centre of mass and perpendicular to the plane of the figure is I . A constant force F is applied to the top of the disc. The acceleration of the centre A of the disc at the instant B is below A (on the same vertical line) will be :, F m, F m + 3 FR 2 4 I, F m + FR 2 4 I, F m + 3 FR 2 I

MARKS App · Accepted Answer

a ¯ A/g = a ¯ A/cm + a ¯ cm/g = R 2 . α + a = R 2 F × 3 R 2 I + F m = 3 FR 2 4 I + F m

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