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A firm employing 30 workers and paying on an average Rs 500 is combined with another firm employing 20 workers paying on an average Rs 600 . What is the average pay of the workers of the combined firm?
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The correct answer is:
$\operatorname{Rs} 540$
Let $\mathrm{n}$ denote number of workers and $\mathrm{x}$, the pay. Let $\mathrm{n}$ denote number of workers ar
$\mathrm{n}_{1}=30, \mathrm{n}_{2}=20, \mathrm{x}_{1}=₹ 500, \mathrm{x}_{2}=₹ 600$
Combined average $=\frac{\mathrm{n}_{1} \mathrm{x}_{1}+\mathrm{n}_{2} \mathrm{x}_{2}}{\mathrm{n}_{1}+\mathrm{n}_{2}}$
$=\frac{30 \times 500+20 \times 600}{30+20}=\frac{15000+12000}{50}$
$=\frac{27000}{50}=540$
Combined average pay $=₹ 540$
$\mathrm{n}_{1}=30, \mathrm{n}_{2}=20, \mathrm{x}_{1}=₹ 500, \mathrm{x}_{2}=₹ 600$
Combined average $=\frac{\mathrm{n}_{1} \mathrm{x}_{1}+\mathrm{n}_{2} \mathrm{x}_{2}}{\mathrm{n}_{1}+\mathrm{n}_{2}}$
$=\frac{30 \times 500+20 \times 600}{30+20}=\frac{15000+12000}{50}$
$=\frac{27000}{50}=540$
Combined average pay $=₹ 540$
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