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Question: Answered & Verified by Expert
A flask contains a mixture of compounds A and B. Both compounds decompose by first-order kinetics. The half-lives for A and B are 300 s and 180 s, respectively. If the concentrations of A and B are equal initially, the time required for the concentration of A to be four times that of B (in s) is : (Use ln 2=0.693)
ChemistryChemical KineticsJEE MainJEE Main 2020 (05 Sep Shift 1)
Options:
  • A 180
  • B 900
  • C 300
  • D 120
Solution:
2232 Upvotes Verified Answer
The correct answer is: 900

Ct=C0e-kt

kA=ln2300        k=ln2T1/2

kB=ln2180

CtA=C0Ae-kAt        

CtB=C0Be-kBt

Ct,BCt,A=C0,BC0,A×ekA-kBt

14=ekA-kBt

 ln14=ln2300-ln2180t

 -2ln2=ln2300-ln2180t

2=120180×300t

t=2×180×300120=900 sec

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