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Question: Answered & Verified by Expert
A force acts on a 30 g particle in such a way that the position of the particle as a function of time is given by x=3t-4t2+t3 where x is in meters and t is in seconds. The work done during the first 4 seconds is
PhysicsWork Power EnergyNEET
Options:
  • A 5.28 J
  • B 450 mJ
  • C 490 mJ
  • D 530 mJ
Solution:
1072 Upvotes Verified Answer
The correct answer is: 5.28 J
v=dxdt=3-8t+3t2

Speed at t=0 is

v0=m/s

Speed at t=4 is

v4=19 m/s

According to work energy theorem

W=12mv42-v02

W=12×0.03×192-32=5.28 J

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