Search any question & find its solution
Question:
Answered & Verified by Expert
A force $\vec{F}=(5 \hat{i}+3 \hat{j}+2 \hat{k}) N$ is applied over a particle which displaces it from its origin to the point $\vec{r}=(2 \hat{i}-\hat{j}) m$. The work done on the particle in joules is
Options:
Solution:
1506 Upvotes
Verified Answer
The correct answer is:
$+7$
$+7$
Work done, W $=\overrightarrow{\mathrm{F}} \cdot \overrightarrow{\mathrm{s}}$
Here $\vec{s}=\vec{r}_f-\vec{r}_i=(2 \hat{i}-\hat{j})$
$$
W=(5 \hat{i}+3 \hat{j}+2 \hat{k})(2 \hat{i}-\hat{j})=10-3=7 \mathrm{~J}
$$
Here $\vec{s}=\vec{r}_f-\vec{r}_i=(2 \hat{i}-\hat{j})$
$$
W=(5 \hat{i}+3 \hat{j}+2 \hat{k})(2 \hat{i}-\hat{j})=10-3=7 \mathrm{~J}
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.