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A force $F$ acting on an object varies with distance $x$ as shown here. The force is in newton and distance is in metre. The work done by the force in moving the object from $x=0$ to $x=6 \mathrm{~m}$ is
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13.5 J
The work done will be the area of the $F$-x graph.
Work done in moving the object from $x=0$ to $x=6 \mathrm{~m}$ is given by
$W=$ area of rectangle + area of triangle
$\begin{aligned} & =3 \times 3+\frac{1}{2} \times 3 \times 3 \\ & =9+4.5=13.5 \mathrm{~J}\end{aligned}$
Work done in moving the object from $x=0$ to $x=6 \mathrm{~m}$ is given by
$W=$ area of rectangle + area of triangle
$\begin{aligned} & =3 \times 3+\frac{1}{2} \times 3 \times 3 \\ & =9+4.5=13.5 \mathrm{~J}\end{aligned}$
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