Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
A galvanometer coil has 500 turns and each turn has an average area of 3×10-4m2. If a torque of 1.5 Nm is required to keep this coil parallel to a magnetic field when a current of 0.5A is flowing through it, the strength of the field (in T) is _________ .
PhysicsCurrent ElectricityJEE MainJEE Main 2020 (03 Sep Shift 2)
Solution:
1070 Upvotes Verified Answer
The correct answer is: 20

τ=M×B=NiAB sin90°

=NiAB=Ni S B

   B=τNiS=1.5500×0.5×3×10-4=20

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.