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A galvanometer has a coil of resistance $100 \Omega$ and gives a full scale deflection for $30 \mathrm{~mA}$ current. If it is to work as a voltmeter of $30 \mathrm{~V}$ range, the resistance required to be added will be
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Verified Answer
The correct answer is:
$900 \Omega$
Required resistance $R=\frac{V}{i_g}-G$
$$
=\frac{30}{30 \times 10^{-3}}-100=900 \Omega
$$
$$
=\frac{30}{30 \times 10^{-3}}-100=900 \Omega
$$
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