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A galvanometer has resistance ' $\mathrm{G}^{\prime}$ and range ${ }^{\prime} \mathrm{V}_{\mathrm{g}}{ }^{\prime}$. How much resistance is required to
read voltage upto ' $\mathrm{V}$ ' volt?
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read voltage upto ' $\mathrm{V}$ ' volt?
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Verified Answer
The correct answer is:
$G\left(\frac{V}{V_{g}}-1\right)$
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