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A galvanometer of resistance, $G$ is shunted by a resistance $S \mathrm{~ohm}$. To keep the main current in the circuit unchanged, the resistance to be put in series with the galvanometer is
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Verified Answer
The correct answer is:
$\frac{G^2}{(S+G)}$
Current will be unchanged if resistance remains same so
$$
\begin{aligned}
& G=\frac{G S}{G+S}+R \\
& R=G-\frac{G S}{G+S} \\
& R=\frac{G^2}{G+S}
\end{aligned}
$$
$$
\begin{aligned}
& G=\frac{G S}{G+S}+R \\
& R=G-\frac{G S}{G+S} \\
& R=\frac{G^2}{G+S}
\end{aligned}
$$
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