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A gas expands $0.25 \mathrm{~m}^3$ at constant pressure $10^3 \mathrm{~N} / \mathrm{m}^2$, the work done is
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The correct answer is:
250 J
From the formula of work done
$W=p \Delta V=10^3 \times 0.25=250 \mathrm{~J}$
$W=p \Delta V=10^3 \times 0.25=250 \mathrm{~J}$
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